2. suppose a new standardized test is given to 100 randomly selected third-grade studentsin new jersey. the sample average scoreyon the test is 58 points and the sample standarddeviationsyis 8 points. a. the authors plan to administer the test to all third-grade students in new jersey. construct a 95% con dence interval for the mean score of all new jersey third graders. b. suppose the same test is given to 200 randomly selected third graders from iowa, pro-ducing a sample average of 62 points and sample standard deviation of 11 points. constructa 90% con dence interval for the di erence in mean scores between iowa and new jersey. c. can you conclude with a high degree of con dence that the population means for iowaand new jersey students are di erent? (what is the standard error of the di erence in thetwo sample means? what is thep-value of the test of no di erence in means versus somedi erence? )

a) n = 100

s = 8

Confidence interval = 95%

Z at 95% = 1.96

Confidence interval formula : to  

Substitute the values :

Confidence interval : to  

Confidence interval : to  

b)n = 200

s =11

Confidence interval = 90%

Z at 90% = 1.64

Confidence interval formula : to  

Substitute the values :

Confidence interval : to  

Confidence interval : to  

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

what is the original number? you forgot to add it.