There are 16 players in my poker group that meets the first tuesday of every month. ten of the players are male and six are female. if five of the guys have arrived and four of the girls have arrived, what is the probability that the next person through the door will be a male?

  Hello mate!

in your group, there are 16 players, 10 males, and 6 females.

in this case, 5 males already arrived (then there are 5 other males left)

and 4 females already arrived (then there are other 2 females left)

then there are a total of 7 players left, where 2 are female and 5 are males.

you want to know the probability that the next person through the door will be a male.

this is the number of male players left, divided by the number of players left: 5/7 = 0.71

then the probability that the next person through the door will be a male is 0.71.

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