Suppose that a die is rolled twice. what are the possible values that the following random variables can take on: (a) the maximum value to appear in the two rolls; (b) the minimum value to appear in the two rolls; (c) the sum of the two rolls; (d) the value of the first roll minus the value of the second roll?

See explanation

Step-by-step explanation:

Suppose that a die is rolled twice. Each time one of 6 numbers (1, 2, 3, 4, 5, 6) can be rolled.

A. the maximum value to appear in the two rolls is 6

B. the minimum value to appear in the two rolls is 1

C. the sum of the two rolls can vary from 2 to 12 (it can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

D. the value of the first roll minus the value of the second roll can very from -5 to 5 (-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5)

Here -5 can be obtained as 1 - 6 (1 on the first roll and 6 on thesecond roll), -4 can be obtained as 1 - 5 or 2 - 6 and so on.

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step-by-step explanation:

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1