20 points
the slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x - 3. what is the
point-slope form of the equation for this line?
o y + 13 = 5(x + 2)
oy- 13 = 5(x - 2)
oy- 2 = 5(x - 13)
o
y + 2 = 5(x + 13)

y + 13 = 5(x + 2)

Step-by-step explanation:

The given equation is in slope- intercept form, that is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x - 3 has slope m = 5

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Using m = 5 and (a, b) = (- 2, - 13), then

y - (- 13) = 5(x - (- 2)), that is

y + 13 = 5(x + 2) ← in point- slope form

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: