Polydactyly is a fairly common congenital abnormality in which a baby is born with one or more extra fingers or toes. it is reported in about one child in every 500 . a young obstetrician celebrates her first 100 deliveries. what is the probability that the obstetrician has delivered no child with polydactyly? (enter your answer rounded to four decimal places.)

Using the principle of binomial probability, the probability that the obstetrician delivers no child with polydactyl is : 0.8186

Recall :

Probability of delivering no child with polydactyl ; x = 0

Substituting the values into the equation

Therefore, the probability that the doctor delivers no child with polydactyl is 0.8186

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There is a 81.86% probability that the obstetrician has delivered no child with polydactyly.

Step-by-step explanation:

There are only two possible outcomes: Either the baby has the anormality, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And is the probability of X happening.

In this problem, we have that:

It is reported in about one child in every 500, so .

A young obstetrician celebrates her first 100 deliveries, so

What is the probability that the obstetrician has delivered no child with polydactyly?

That is P(X = 0)

There is a 81.86% probability that the obstetrician has delivered no child with polydactyly.

option: d is correct

step-by-step explanation:

it has the same slope and a different y-intercept

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