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Mathematics, 08.10.2019 19:30 robertgib76

Which shows a recursive and an explicit formula for a sequence whose initial term is 14 and whose common difference is βˆ’4? a. a(1) = 14; a(n) = (n βˆ’ 1) βˆ’4; a(n) = 14 + (n βˆ’ 1)(βˆ’4) b. a(1) = 14; a(n) = (n + 1) βˆ’4; a(n) = 14 + (n βˆ’ 1)(βˆ’4) c. a(1) = 14; a(n) = (n βˆ’ 1) βˆ’ 14; a(n) = 14 + (n βˆ’ 1)(βˆ’14) d. a(1) = 14; a(n) = (n + 1) βˆ’ 14; a(n) = 14 + (n + 1)(14)

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