Ineed with all of these. i am in online school so i don't have a teacher to explain this to me and am struggling.

1.)what is the directrix of the parabola given by the equation r= 2/1+sinθ ?
rsinθ = 2
sinθ = 2
rcosθ = 2
r = 2
2.) choose the equation of the conic section described. a parabola with focus at the pole and directrix rsinθ = - 5
3.)choose the equation of the conic section described.
focus at the pole, eccentricity of 2/3, vertical directrix 2 units to the left of the pole
4.)write the equation of the conic section satisfying the given conditions.
focus at the pole, e = 3/4, horizontal directrix 2 units above the pole
5.)the equation of a parabola is r= 6/1+cosθ. the vertex of the parabola is located at
(3, 0°)
(6, 0°)
(3, 180°)
(6, 180°)

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step-by-step explanation:

1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!