Find the center, vertices, and foci of the ellipse with equation 4x^2 + 9y^2 =36

The center, vertices and foci of the ellipse with equation respectively

Solution:

The equation of ellipse with centre (0, 0) in the form of   --- eqn 1

Where,

x is the major axis  

Centre (0, 0)

Vertices is      

Foci is where

Now given that the equation of ellipse is

--- eqn 2

On dividing equation (2) by 36,

On comparing equations (1) and (2),  

We get a = 3, b= 2  

So centre of

Vertices of

Foci of

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this