Camille and hiroki have decided to start walking for exercise. camille is going to walk 777 miles the first day and 333 miles each day after that. hiroki is too busy to walk on the first 222 days, so he decides to walk 555 miles each day until he has walked the same number of miles as camille. if camille and hiroki will have walked the same number of miles, how many days will camille have walked?

7 days

Step-by-step explanation:

Camille and Hiroki have decided to start walking for exercise. Camille is going to walk 7 miles the first day and 3 miles each day after that. Hiroki is too busy to walk on the first 2 days, so he decides to walk 5 miles each day until he has walked the same number of miles as Camille.

Camille will walk x days, so: 7 + 3(x-1) miles

Hiroki will walk the same miles, but 2 days less so: 5(x-2)

same amount of miles:

5(x-2) = 7 + 3(x-1)

5x - 10 = 7 + 3x - 3

5x - 3x = 10 + 7 - 3

2x = 14

x = 7

If Camille and Hiroki will have walked the same number of miles, how many days will Camille have walked?

Camille will have walked 7 days.

the answer will be

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;