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on a coordinate plane, a parabola opens up. it starts in quadrant 1, crosses the x axis where the vertex is in quadrant 4, and crosses the x-axis back into quadrant 1. which function could be represented by the graph on the coordinate plane? f(x) = (x – 8)2 + 6 f(x) = (x + 8)2 + 6 f(x) = (x + 8)2 – 6 f(x) = (x – 8)2 – 6