M& m plain candies come in various colors. according to the m& m/mars department of consumer affairs, the distribution of colors for plain m& m candies is as follows. color purple yellow red orange green blue brown percentage 23% 21% 19% 10% 7% 7% 13% suppose you have a large bag of plain m& m candies and you choose one candy at random. (a) find p(green candy or blue candy). are these outcomes mutually exclusive? why? yes. choosing a green and blue m& m is possible. yes. choosing a green and blue m& m is not possible. no. choosing a green and blue m& m is not possible. no. choosing a green and blue m& m is possible. (b) find p(yellow candy or red candy). are these outcomes mutually exclusive? why? yes. choosing a yellow and red m& m is not possible. yes. choosing a yellow and red m& m is possible. no. choosing a yellow and red m& m is possible. no. choosing a yellow and red m& m is not possible. (c) find p(not purple candy).

(a) P(green candy or blue candy)=14%

These outcomes are mutually exclusive. Choosing a green and blue M&M is not possible.

(b) P(yellow candy or red candy)= 40% These outcomes are mutually exclusive. Choosing a yellow and red M&M is not possible.

(c) P(not purple candy)=77%

Step-by-step explanation:

To get the probability  equally likely of having a candy we use the following formula

P=# of possibilities that meet the condition / #of equally likely possibilities.

In this case,  we are consider 100 candies  as the number of equally likely possibilities.

P(green candy or blue candy)

green candy= 7 candies over 100 ( 7 %)

blue candy= 7 candies over 100 ( 7 %)

P(green candy or blue candy)= 7+7 / 100= 14/100=14%

Are these outcomes mutually exclusive? Yes. Choosing a green and blue M&M is not possible. Both can't occur at the same time.

(b) P(yellow candy or red candy)

yellow candy= 21 candies over 100 ( 21 %)

red candy= 19 candies over 100 ( 19 %)

P(yellow candy or red candy)= 21+19 / 100= 40/100=40%

Are these outcomes mutually exclusive? Yes. Choosing a green and blue M&M is not possible.

(c) P(not purple candy)= to get this probability we have to consider the others possibilities, we can get Yellow, Red, Orange, Green, Blue or Brown,  

that means 21+ 19+ 10+ 7+ 7+ 13=77

P(not purple candy)= 77/100= 77%

f(x)=2/3x-8, which give g(x) the greatest value.

step-by-step explanation: