Which equation has the solutions x= 5 ± 2 square root 7 all over 3
1. 3x2 – 5x + 7 = 0
2. 3x2 – 5x – 1 = 0
3. 3x2 – 10x + 6 = 0
4. 3x2 – 10x – 1 = 0

  4.  3x^2 – 10x – 1 = 0

Step-by-step explanation:

You can write the quadratic from the roots:

  0 = (x - (5-2√7)/3)(x - (5+2√7)/3)

  = (x -5/3)^2 -(2√7/3)^2

  = x^2 - 10/3x +25/9 -28/9

  = x^2 -10/3x -1/3

Multiplying by 3 gives ...

  0 = 3x^2 -10x -1

step-by-step explanation:

4  

25

5258y

54.

t5

5r

54

5856

542

5458

86

.8558.65

565

565

55898

786

8/95

5896

8656265

556478