Find a polynomial equation that has zeros at x = −2, x = 0, x = 3 and x = 5
a) y = (x + 2)(x − 3)(x − 5)
b) y = (x − 2)(x + 3)(x + 5)
c) y = (x − 2)(x − 3)(x − 5)
d) y = x(x + 2)(x − 3)(x − 5)

250

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

investment b is an ordinary annuity with $3,909.64 in the account after one year.

step-by-step explanation: