Which ordered pair is not a solution of f(x)= 2x + 9?

what you do is subsitute the first number in the pair for x and subsitute the second number for f(x) you must have made a typing error when typing the options since they are alll correct proabably one of the two (7,23) is mistyped basically one example is the point (0,9) x=0 f(x)=9 subsitute 9=2(0)+9 9=0+9 9=9 this is true so it is a soltuion the answer choice is not listed (probably because of a typo)

(3, 14)

Step-by-step explanation:

To find the order which is a solution,we will need to check;

f(x) = 2x + 9

(0, 9)

x = 0

we replace x by 0 in the equation

f(0) = 2(0) + 9

9 = 9

Therefore ( 0, 9) is a solution of the function

we check the next pair (7, 23)

f(7) = 2(7) + 9 = 14+9=23

23 = 23

(7, 23) is a solution to the function

we move to the next pair

(3, 14)

f(3) = 2(3) + 9

= 6 + 9

= 15

14 = 15

since 14 is not equal to 15

Therefore (3, 14) is not a solution to te function

n word

step-by-step explanation:

what lives in the hood

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: