Lance decides to buy three sweatshirts and a pair of sweatpants. he has $100 in his wallet. if the price of the sweatpants is $ 40, what is the highest price of a sweatshirt?

answer asap and write and solve inequality.

100 = 40 + 3x

Subtract 40 from each side

60 = 3x

Divide each side by 3

20 = x

The highest price of a sweatshirt can be $20

100 = 40 + 3(20)

Step-by-step explanation:

We know that Lance wants to buy three sweatshirts and a pair of sweatpants. We then see that sweatpants cost $40.

100 = 40 + 3x

Since Lance has 100 dollars right now, we can erase 40.

Currently, Lance has 60 dollars left.

Since he buys 3 sweatshirts, we have to divide 60 by 3.

Each sweatshirt would cost 20 dollars.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg