Suppose that the heights of the individuals in a certain population have a normal distribution for which the value of the mean θ is unknown and the standard deviation is 2 inches. suppose also that the prior distribution of θ is a normal distribution for which the mean is 68 inches and the standard deviation is 1 inch. if 10 people are selected at random from the population, and their average height is found to be 69.5 inches, what is the posterior distribution of θ?

1. 22

2. 1

3. 7

4. 18

step-by-step explanation

e2020 got it right

5.25 ounces

step-by-step explanation:

divided 3/4 and 6

what "following statement"?

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!