Two cars simultaneously left points a and b and headed towards each other, and met after 3 hours and 15 minutes. the distance between points a and b is 364 miles. what is the speeds of the cars, if one of the cars travels 12 mph faster than the other?

  50 mph, 62 mph

Step-by-step explanation:

Their total speed is found from ...

  speed = distance/time

  speed = (364 mi)/(3.25 h) = 112 mi/h

If s is the speed of the slower car, then ...

  s + (s+12) = 112 . . . . . their total speed is 112 mph

  2s = 100 . . . . . . . . . . simplify, subtract 12

  s = 50 . . . . . . . the speed of the slower car

  s+12 = 62 . . . . the speed of the faster car

Speed of one car=50 mph

Speed of another car=50+12=62 mph

Step-by-step explanation:

Speed of one  car= x mile/hr

Speed of another car=(x+12) miles/hr

Time=3 hours 15 minutes=

Because 1 hr=60 minutes

Distance between point A and B=364 miles

Distance =

According to question

Speed of one car=50 mph

Speed of another car=50+12=62 mph

there are no figures how am i supposed to answer this question

step-by-step explanation:

b mark me branliest thx

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