Charcoal is found in a cave. it is determined that the amount of c – 14 present is 60% the amount when the wood was burned. if the c – 14 has a half-life of 5700 years, how long ago was the wood burned?

The wood was burned 4257 years ago.

Step-by-step explanation:

The amount of C-14 present can be modeled by the following exponential function.

In which C is the amount remaining, is the initial amount, r is the rate that the amount decrases, and t is the time in years.

The C – 14 has a half-life of 5700 years.

This means that

How long ago was the wood burned?

To solve this equation for t when , the first step is finding the rate that the amount decreases. For this, we apply the half-life information in the equation.

First step: Find the rate that the amount of C-14 decreases.

The next step here is applying ln, since ln and e are inverse functions.

Final step: Find the time

We have that , .

So:

Applying the ln in both sides of the equality.

The wood was burned 4257 years ago.

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0