The surface areas of two similar figures are given. the volume of the larger figure is given. find the volume of the smaller figure. s. a. = 192 m s. a. = 1728 m² v = 4860 m3

The volume of smaller figure is 180 m³

Step-by-step explanation:

Consider the provided information.

The ratio of the surface areas is equal to the square of scale factor K.

let K₁ and K₂ is the scale factor

Thus

Substitute the respective values as shown.

It is given that the volume of larger figure is 4860 m³.

Let V₁ and V₂ is the volume of small and larger figure respectively.

The ratio of the volume is equal to the third power of scale factor K.

Thus

Substitute the respective values as shown.

Hence, the volume of smaller figure is 180 m³

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!