What is the equation of the line that is parallel to the given
line and passes through the point (-2, 2)?
-+
o y=x+4
oy= {x+ }
o y = -5x + 4
o y=-5x + 1}
6
5
4 3 2
1
1 2 3
4 $ 6x
(0, -3)
(-5,-4)

no

step-by-step explanation:

answer

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen