Amotorist is driving eastbound at the posted maximum speed along a stretch of university parkway in baltimore. the probability that the motorist approaching a red light at the san martin/39th st intersection is 0.4. the probability that the motorist encounters a red light again at the next intersection (canterbury rd) is 0.7. if the motorist does not encounter a red light at the first intersection (san martin/39th), then the probability the motorist encounters a red light at the second intersection is 0.2. if in a certain instance the motorist is observed to have encountered a red light at the canterbury rd intersection, what is the probability the motorist encountered a red light at the san martin/39th intersection

0.7

Step-by-step explanation:

Let A and B be the events

A = the motorist encountered a red light at the 1st intersection

B = the motorist encountered a red light at the 2nd intersection

Then we have

We want to find P(A|B), the probability that A occurred given that B occurred.

Using Bayes' Theorem we have

So,  

and we just need to find P(B)

But

and  

Since  

We have

and finally,

0.7 i had the same question on edge

Step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet