What is the vertex of the quadratic function f(x) = (x-6)(x+2)

For this case we have the following function:

We rewrite the function making distributive property.
We have then:

To find the vertex of the function, we derive:

We equal zero and clear the value of x:

We evaluate the function for the value of x obtained:

Then, the vertice of the parabola is:

the vertex of the quadratic function f(x)=(x-6)(x+2) is:

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