In 2002, tim was twice as old as sue. in 1997 the sum of their ages was 32. in what year will sue's age be three-fourths tim's age

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = X years

In 1997, Let Sue's age = Y years

After 5 years in 2002, Tim's age = (X+ 5) years

After 5 years in 2002, Sue's age = (Y + 5) years

Now, According to question,

X + Y = 32    (sum of their ages) .......(1)

Y = 32 - X

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of Y in (2)

X + 5 = 2 (32 - X + 5)

X + 5 = 2 (37 - X )

X + 5 = 74 - 2X

3X = 69

X = 69/3 = 23

Now ∵ Y = 32 - X  and X = 23

∴ Y = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after t years = (9 + t) years.

Tim's age after t years = (23 + t) years

According to question,

The Year in which Sue's age will be three-fourth times of Tim's age is:

= (1997 + 33) = 2030.

examine the two-step equation.

−  

7

4

+  

x

4

= 2

which property of operations allows you to add the same constant term to both sides?

multiplication property of equality

division property of equality

addition property of equality

subtraction property of equality

step-by-step explanation: