![\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-1)}}}\implies \cfrac{-3}{0+1}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-3}[x-\stackrel{x_1}{(-1)}] \\\\\\ y=-3(x+1)\implies y = -3x-3](/tpl/images/0278/2211/87f6a.png)
Write the equation of the line passing through (-1,0) and (0, -3).
ulas
3x - y = 3
...
Mathematics, 01.10.2019 01:20 jazminemartinez3223
Write the equation of the line passing through (-1,0) and (0, -3).
ulas
3x - y = 3
x - 3y = 3
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6: 32
3x + y = -3
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x + 3y = -3
Answers: 2
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