Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)if the coin is flipped 3 times, what is the probability of getting exactly 1 head? give your answer to four decimal places b)if the coin is flipped 5 times, what is the probability of getting exactly 2 tails? give your answer to four decimal places c)if the coin is flipped 4 times, what is the probability of getting at least 3 tails? give your answer to four decimal places

a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

Now,

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

Hence, a) 0.2222, b) 0.3292, c) 0.1111

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4