Question 1 (multiple choice worth 1 points)
(02.04 mc)
choose the equation that represents a line that passes through points (-3, 2) and (2, 1).
5x + y = -13
5x - y = 17
ox - 5y = -13
x + 5y = 7

x+5y = 7

Step-by-step explanation:

The formula for finding the equation of a line is expressed as y= mx+c where;

m is the slope or gradient of the line defined as m = ∆y/∆x = y2-y1/x2-x1

Given the points (x1,y1) = (-3, 2) and (x2,y2) = (2, 1).

m = 1-2/2-(-3)

m = -1/5

To calculate the intercept c we will substitute any of the points given into the equation of the line to have;

y = mx+c

Using the point (-3,2)

Where x = -3, y=2

2 = (-1/5)(-3) + c

2 = 3/5+c

c = 2-3/5

c = 7/5

Substituting the value of m = -1/5 and c = 7/5 into the expression of equation of a line we have;

y = (-1/5)x+7/5

Multiplying through by 5 gives,

5y= -x+7

5y+x=7

= x+5y = 7 (D)

answer is c

step-by-step explanation:

81/12=324/x

x=48