Two consecutive integers are such that their sum is greater than 98 decreased by twice the larger. find the smallest possible values for both integers.

answer:

24 and 26

step-by-step explanation:

x = smaller

x+2 = larger

their sum, x+(x+2), is greater than, > , 98 decreased by, -, twice the

larger, 2(x+2).

so:

x+(x+2) > 98-2(x+2)

  x+x+2 > 98-2x-4

  2x+2 > 94-2x

  2x+2x > 94-2

    4x > 92

      x > 23

since x is the smaller, it must be greater than 23,

and the larger, x+2, must be 25 or larger.

the smallest two such consecutive even integers are 24 and 26.

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !