Hey, can you factor completely 6x^2+11x-10 as (6x-4)(x-15/6)?

i know the proper way is (3x−2)(2x+5) but i did it this way and want to know if it is correct.

The answer to your question is below

Step-by-step explanation:

Factor completely                          6x² + 11x - 10

1.- Multiply 6 by -10 = -60

2.- Find the prime factors of -60

       -60     2

       -30     2

       -15      3                60 = 2 x 2 x 3 x 5

       -5        5              Combine these numbers so, if add them up give +11

       -1                          and if multiply equals -60.

                                   These numbers are +15 and -4

                                    Instead of writing +11x, in the original equation, write,                

                                    + 15x - 4x.

                                    6x² - 4x + 15x - 10       Factorize like terms

                                    2x(3x - 2) + 5(3x - 2)   Factorize like terms

                                    (3x - 2) (2x + 5).

Sorry, I could not get (6x - 4) (x - 15/6)

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316