Compute the total hours on a weekly time card.
terry bartlett worked from 7: 00 a. m. to 10: 45 a. m. and from 12: 30 p. m. to
3: 15 p. m. find the total hours.
step: calculate the total hours. total hours = sum of daily hours
10: 45 - 7: 00 = 3h: 45min
3: 15 - 12: 30 = 2h: 45min
3h: 45min + 2h: 45min = 5h: 90min = 6 hours
review exercises
john kim works in a hospital. use his time card to find his total hours worked
each day and his total hours for the week. round off the total hours each day to
the nearest quarter hour.
employee time card
central arkansas hospital
employee name: joht kim
_ department: radiology
date in out in out total
27.
9/1 6: 45 a. n. 11: 30 a. m. 12: 00 pm 3: 45 pm
28.
9/2
7: 00 a. m. 11: 30 am
29.
12: 00 pm 3: 45 2.m.
6: 56 am
30.
11: 45 am 12: 30 pm 4: 00 pm
9/4
31.
6: 45 a. m. 12: 50 pm 1: 50 pm 3: 00 pm
9/5
7: 10 am 11: 30 am 12: 30 pm 4: 25 ..
32.
employee signature: sehr kim
total hours
sun.
mon
thur
sat
week
porte
tea

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.

answer: i think it's a

step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh