Suppose that n is a function of a scalar u in a reference frame r such that as u varies, n changes in such a way that it always remains perpen- dicular to a unit vector k fixed in r. let l be a line parallel to n and let ni be a unit vector parallel to a line l'fixed in r and perpendicular to k. we discussed the relation rdn/dz k x n de/dz. where e is the angle between l'and l'. show that k xn=-sinb cose ñ2 where n2 is a unit vector perpendicular to both k & nn with the sense of n2 defined in such a way that ni x i2

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy

answer: a

step-by-step explanation: the answer is a due to the rule of symmetry; that a line of symmetry must divide a figure into 2 pieces that are the exact same, only reflected over a line of symmetry. b and c do not have lines of symmetry and would not divide the figure evenly, thus making the answer a.