Ineed these now :
14y-5(3-2y)
7(y+3)-2y
-4(x+6)+2(x-2)
6x-3x+1-5x+2
14x-5(-2x+3)
3(x-y+5)

1. 14y-5(3-2y)

14y-15+10y

Ans = 24y-15

2. 7(y+3)-2y

7y+21-2y

Ans = 5y+21

3. -4(x+6)+2(x-2)

-4x-24+2x-4

Ans = -2x-28

4. 6x-3x+1-5x+2

Ans = -2x+3

5. 14x-5(-2x+3)

14x+10x-15

Ans = 24x-15

6. 3(x-y+5)

Ans = 3x-3y+15

Step-by-step explanation:

You have to first multiply the number outside the parantheses to the number(s) inside the parantheses.

Then, you have to combine all the like terms.

And then there's your answer !!!

GOOD LUCK !!!

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .