There is a 0.9986 probability that a randomly selected 33-year-old male lives through the year. a life insurance company charges $182 for insuring that the male will live through the year. if the male does not survive the year, the policy pays out $110 comma 000 as a death benefit. complete parts (a) through (c) below.

Expected Value = -$42 (loss of 42 dollars)

Step-by-step explanation:

Complete Question Below:

"There is a 0.9986 probability that a randomly selected 33-year-old male lives through the year. A life insurance company charges $182 for insuring that the male will live through the year. If the male does not survive the year, the policy pays out $110 comma 000 as a death benefit. If a 33-year-old male purchases the policy, what is his expected value?"

We can say P(survival) = 0.9986 and thus P(not survival) = 1 - P(survival) = 1-0.9986 = 0.0014

Also,

In case 33 year old doesn't live, the payment would be 100,000 - 182 = $99,818

And

In case 33 year old lives, the payment is

-$182

We know, the expected value is the sum of the product of each possibility with its probability.

This means a loss of $42 (or -$42)

find out the value of b

step-by-step explanation:

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3