Mr. smith has 15.6 pounds of oranges to pack for shipment. he can ship 2.4 pounds of oranges in a large box and 1.2 pounds in a small box. if he ships 5 large boxes, what is the minimum number of small boxes required to ship the rest of the oranges?

3 boxes.

Step-by-step explanation:

Let x represent number of 1.2 pounds boxes.

We have been given that Mr. Smith has 15.6 pounds of oranges to pack for shipment. He can ship 2.4 pounds of oranges in a large box and 1.2 pounds in a small box.

The oranges covered in x small boxes would be    

Oranges packed in 5 large boxes would be .

We can represent our given information in an equation as:

Therefore, the minimum number of small boxes required to ship the rest of the oranges would be 3 boxes.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

5

10

15

20

25

30

35

40

45

50

55