Jackie cut a 2-yard spool into 5 equal lengths of ribbon.
a. what is the length of each ribbon in yards? draw a tape diagram to show your thinking.
b. what is the length of each ribbon in feet? draw a tape diagram to show your thinking.

a. yard

b. 1.2 feet

Step-by-step explanation:

a. Jackie cut a 2-yard spool into 5 equal length of ribbon.

We will divide 2 yard by 5 = 2 ÷ 5 =   yard

5 units = 2 yard

1 unit = yard

Check : + + + + = = 2

b. Length of each ribbon in feet

Since 1 yard = 3 feet

therefore, 2 yard = 3 × 2 = 6 feet

6 feet in to 5 equal part = 6 ÷ 5

                                       = 1.2 feet

check :   1.2 + 1.2 + 1.2 + 1.2 + 1.2 = 6.0 feet

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!