The function
y = 2x + 2 and
y = -x + k intersect at
the point (2,6). find the
value of k.

k=8

The problem:

The function y=2x+2 and y=-x+k intersect at the point (2,6).

Find the value of k.

Step-by-step explanation:

(2,6) is a point contained by both y=2x+2 and y=-x+k.

Let's see if it actually on y=2x+2.

x=2,y=6

y=2x+2

6=2(2)+2

6=4+2

6=6 is true so it (2,6) is on y=2x+2.

Now we want k such that (2,6) is on y=-x+k.

6=-2+k

Add 2 on both sides:

8=k

So k=8.

k = 8

Step-by-step explanation:

y = 2x + 2    

y = -x + k

2x + 2  = - x +k

3x = k - 2

x= 2 : k-2= 6

k = 8

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho