Me

two similar triangles are shown on the coordinate grid:

a coordinate grid is shown from positive 6 to negative 6 on the x-axis and from positive 6 to negative 6 on the y-axis. a triangle mno is shown with vertex m on ordered pair negative 2, 4, vertex n on ordered pair 0, 0, and vertex o on ordered pair negative 6, negative 2. a triangle m prime n prime o prime is also shown with vertex m prime on ordered pair 1, 2, vertex n prime on ordered pair 0, 0, and vertex o prime on ordered pair 3, negative 1.
which set of transformations has been performed on triangle mno to form triangle m′n′o′? (5 points)

a
dilation by a scale factor of 2 followed by reflection about the x-axis

b
dilation by a scale factor of fraction 1 over 2 followed by reflection about the x-axis

c
dilation by a scale factor of 2 followed by reflection about the y-axis

d
dilation by a scale factor of fraction 1 over 2 followed by reflection about the y-axis

D: Dilation of 1/2 and reflected across the y-axis.

Step-by-step explanation:

The smaller triangle is half the size of the original, and the smaller (after dilation) is reflected across the y-axis to rest where it is now.

Step-by-step explanation:

To know the transformation applied, we just need to look the graph.

ΔMNO is the original figure. You can see already that the original figure is bigger, that means the transformation must be down by a fractional scale factor, which give this result.

So, our answer must contain a dilatio of a scale factor of 1/2, because the original figure was decreased.

Now, if you look closer, notice that the vertical axis works as a mirror, in other words, both figures are kind of symmetrical regarding the vertical axis. That means the original triangle was reflected across the vertical axis. So, that's the second transformation.

Therefore, choice d. expresses all these transformations:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation: