Mathematics, 26.09.2019 20:00 Cartucho1978
He point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals startfraction one-fourth endfraction left-parenthesis x minus 12 right-parenthesis.(x – 12). what is the standard form of the equation for this line?
x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2
Answers: 3
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He point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 =...
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