In a refrigerator, there are 6 bottles of soft drinks (each a different brand) and 8 cans of juice (each a different type). how many combinations can be made with one soft drink and one fruit drink?
a. 1
c. 36
b. 14
d. 48

The number of ways of choosing 1 soft drink from 6 soft drinks is 6C1 = 6!/((6-1)! * 1!) = 6!/(5!) = (6*5*4*3*2*1)/(5*4*3*2*1) = 6.

Similarly, the number of ways of choosing 1 fruit juice from 8 cans of juice is 8C1 = 8!/((8-1)! * 1!) = 8!/7! = 8

number of combinations of 1 soft drink AND 1 fruit drink = 6 x 8 = 48

D [48]

40 & 50 in the right corner are the complementary angles as when placed in a sum (added together) they make 90°

Idon’t feel like doing the math but you need to do 2.24 divided by 7