Series of questions answer them all.
1st q 5x + 5x = 10x a0
2nd q (13)^2(13)^-4(13)^5 =
3rd q (4x)^-2(4x)^3(4x)^9 = (
4th q 6xy^-2 / x^-3 =
5th q (1/4x)^-2 / x^2
6th q 3x^2(9x)^0 = x

practice. practice. practice.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet