What are the zeros of the function f(x)=x^2+8x+4, expressed in the simplest radical form ?

Step-by-step explanation:

The zeros of f is when f=0.

So we need to solve:

-----------------------------------------------------------------------------------------------------

I'm going to choose completing the square.

Subtract 4 on both sides:

Add (8/2)^2 on both sides:

Write left hand side as a square:

Take the square root of both sides:

Simplify right hand side:

Subtract 4 on both sides:

---------------------------------------------------------------------------------------------

You could also go with quadratic formula:

We need to use this formula:

.

I'm going to evaluate first.

So now we have this so for with the formula:

Simplifying the denominator gives:

Now is there a perfect square in 48?  Yes, 16 is a perfect square factor in 48.

So we can write:

Reduce fractions:

0 is its x and y coordinate