Asurvey of athletes at a high school is conducted, and the following facts are discovered: 33% of the athletes are football players, 66% are basketball players, and 20% of the athletes play both football and basketball. an athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player?

The probability that the athlete is either a football player or a basketball player is 79%

Football players=33%

Basketball players=66%

Both football and basketball=20%

Probability=Football players + Basketball players

- Both football and basketball

Probability= 33% + 66% - 20%

Probability=79%

Inconclusion The probability that the athlete is either a football player or a basketball player is 79%

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Step-by-step explanation:

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Now, these percentages are representations regarding the total number of students.

It's important to know that percentages can also represents probabilities, like in this case.

So, basically, there's 33% to chose a football player, there's 66% to choce a basetball player, and there's 20% to choce a student who plays both football and basketball.

Now, if we want to know the probability of choosing someone who plays either football or baskebatll, then we must sum 33% + 66% = 99%.

Therefore, the probability is 99% of picking a student who plays either football or basketball.

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-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363