Ineed your right now with a math problem. it says a new cruise ship line has just launched 3 new ships: the pacific paradise, the caribbean paradise, and the mediterranean paradise. the caribbean paradise has 29 more rooms deluxe staterooms than the pacific paradise. the mediterranean paradise has 15 fewer deluxe staterooms than four times the number of deluxe staterooms on the pacific paradise. find the number of deluxe staterooms for each of the ships if the total number of deluxe staterooms for the three ships is 1016.

Caribbean Paradise=196

Pacific Paradise=167

Mediterranean Paradise=653

Let's break it down.

The Caribbean Paradise has 29 more rooms deluxe staterooms than the Pacific Paradise.

Let's make C= Caribbean Paradise and P= pacific Paradise

C=P+29

The Mediterranean Paradise has 15 fewer deluxe staterooms than four times the number of deluxe staterooms on the pacific paradise

M=Mediterranean Paradise

M=(4*P)-15

Find the number of deluxe staterooms for each of the ships if the total number of deluxe staterooms for the three ships is 1016

Okay so C+P+M=1016

So just combine the first two problems with the last

It changes into

(P+29)+P+M=1016

2P +29+M=1016

Then replace M

2P+29+4P-15=1016

Combine like terms

6P+14=1016

Then solve for P

6P+14(-14)=1016(-14)

6P=1002

6P/6=1002/6

P=167

Then plug in P=167 into your first two formulas

C=P+29

C=(167)+29

C=196

M=(4*P)-15

M=(4*167)-15

M=(668)-15

M=653

i think the answer is b)

step-by-step explanation:

109 is the nearest whole number/final answer! : )