Afactory produces 1,250,000 toys each year. the number of toys is expected to increase by about 150% per year. which model can be used to find the number of toys being produced, n (in millions), in t years?

a. n= 2.5(1.5)/t, t cannot = 0
b. n= 1.5t^2 + 1.25
c. n= 1.5t + 1.25
d. n= 1.25(2.5^t)

Hello mate!

The initial number produces is 1,250,000 toys per year, and you expect to increase by 150% per year.

an increase of 150% (1.5 in decimal form) means that after a year, the amount of toys produced are:

1,250,000 + 1.5*1,250,000 = 1,250,000*(1 + 1.5) = 1,250,000*2.5

and each year, you multiply the previous quantity by 2.5

then the model (in millions) is,  as a function of years:

p(0) = 1.25

p(1) = 1.25*2.5

p(2) = 1.25*2.5*2.5

and so on; you can see that:

p(t) = 1.25*(2.5^t)

So the right option is D.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i