An assembly consists of three mechanical components. suppose that the probabilities that the first, second, and third components meet specifications are 0.95, 0.98, and 0.99, respectively. assume that the components are independent. determine the probability mass function of the number of components in the assembly that meet specifications. 3.1.18 the distribution of the time until a web

P(X=0)=1x10^-5

P(X=1)=1.67x10^-3

P(X=2)=0.0766

P(X=3)=0.9217

Step-by-step explanation:

X="The number of components that meet specifications"

A="The 1st component meet the specification"

B="The 2nd component meet the specification"

C="The 3rd component meet the specification"

The events are independents

P(A)=0.95

P(B)=0.98

P(C)=0.99

P(X=0)=P(A'∩B'∩C')=P(A')P(B')P(C')=(1-P(A))(1-P(B))(1-P(C))=

(1-0.95)(1-0.98)(1-0.99)=0.05x0.02x0.01=1x10^-5

P(X=0)=1x10^-5

P(X=1)=P(A∩B'∩C')+P(A'∩B∩C')+P(A'∩B'∩C)

P(X=1)=P(A)P(B')P(C')+P(A')P(B)P(C')+P(A')P(B')P(C)

P(X=1)=P(A)(1-P(B))(1-P(C))+(1-P(A))P(B)(1-P(C))+(1-P(A))(1-P(B))P(C)

P(X=1)=(0.95)(1-0.98)(1-0.99)+(1-0.95)(0.98)(1-0.99)+(1-0.95)(1-0.98)(0.99) P(X=1)=1.67x10^-3

P(X=2)=P(A'∩B∩C)+P(A∩B'∩C)+P(A∩B∩C')

P(X=2)=P(A')P(B)P(C)+P(A)P(B')P(C)+P(A)P(B)P(C')

P(X=2)=(1-P(A))P(B)P(C))+P(A)(1-P(B))P(C)+P(A)P(B)(1-P(C))

P(X=2)=(0.05)(0.98)(0.99)+(0.95)(0.02)(0.99)+(0.95)(0.98)(0.01)

P(X=2)=0.0766

P(X=3)=P(A∩B∩C)=P(A)P(B)P(C)=P(A)P(B)P(C)= (0.95)(0.98)(0.99)=

P(X=3)=0.9217

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

c. side angle side. u shares the same sides