7.) 4(3x - 2) = 9z-7
8.)7s+2=4(s+1)
9.) 2/3(3q + 6) = 8
with these 3 questions

Answers:

7. )4(3x - 2) = 9z-7

Multiply the bracket by 4

(4)(3x)=12x , (4)(-2)=-8

12x-8=9z-7

move 8 to the other side

sign changes from -8 to +8

12x-8+8=9z-7+8

12x=9z+1

divide both sides by 12

12x/12=9z/12+1/12

reduce 9z/12 by dividing by 3

9z/3=3

12/3=4

x=3/4z+1/12

8. ) 7s+2=4(s+1)

Multiply the bracket by 4

(4)(s)=4s  , (4)(1)=4

7s+2=4s+4

7s-4s+2=4s-4s+4

3s+2=4

3s+2-2=4-2

3s=2

divide both sides by 3

3s/3=2/3

s=2/3

9).  2/3(3q + 6) = 8

(2/3)(3q)

Cross out 3 and 3q divide by 3 and then becomes 2q

2/3*6 - Cross out 3 and 6, divide by 3 and then becomes 4

2q+4=8

2q+4-4=8-4

2q=4

divide both sides by 2

2q/2=4/2

q=2