Average monthly temperature month temperature january 45 degrees february 42 degrees march 54 degrees april 62 degrees may 78 degrees june 85 degrees july 92 degrees august 94 degrees september 89 degrees october 78 degrees november 65 degrees december 54 degrees the average monthly temperatures for the city of mathville are given in the chart above. one year, january's average temperature was 7 degrees warmer, february's was 3 degrees cooler, june's was 2 degrees cooler, august's was 3 degrees warmer, and november's was 7 degrees warmer. what did this do to the average yearly temperature? a) the average remained the same. b) the average increased by 1°. c) the average decreased by 1°. d) the average increased by 17°.

From what I understand the answer is B

Step-by-step explanation:

calculate the difference between the averages that we're dated from each month them look between your answers and from there calculate till you can an answer that fits for each one. The correct one being B

x is the average yearly temperature so another way to work this out as add all of the averages up and then work through by diving each average by twelve them look at the difference between the two

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.