Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?

Complete Question:

Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?  For what values?(Make sure to use an inequality)

y < 3

Step-by-step explanation:

The given two fractions are:

and

We have to tell for which range of values is the value of first fraction larger than the second fraction. This can be done by setting up an inequality as shown:

The range of y which will satisfy this inequality will result in first fraction of larger value as compared to the second fraction.

Multiplying both sides of inequality by 12, we get:

This means, for y lesser than 3, the value of first fraction is larger than the second one.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

steve should create a type of business report called a business plan. the correct option among the options that are already given in the question is the last or the fourth option. this business report created by steve will actually influence the investors about investing their money in steve's business. this business report will have all the details about the business, the amount of investment required and the amount of expected profit.