How many ways can 6 different prize be distributed equally among three superior students?

There are 90 ways to distribute the prizes

Step-by-step explanation:

* Lets explain how to solve the problem

- There are 6 different prize distributed equally among 3 super students

∵ There are 6 prize are to be equally distributed among 3 students

∴ Each student will get ⇒ 6 ÷ 3 = 2

∴ Each student takes 2 prize

* Order doesn't matter here because the 3 students are super

  so we can start with any one of them

# The 1st student will get 2 prize from 6

∴ The choices = 6C2

# The 2nd student will get 2 prize from remaining 4 prize

∴ The choices = 4C2

# The 3rd student will get 2 prize from remaining 2 prize

∴ The choices = 2C2

* To find the total choices multiply the three choices above

∴ The total choices = 6C2 × 4C2 × 2C2

∴ The total choices = 15 × 6 × 1 = 90 choices

* There are 90 ways to distribute the prizes

a. 74 degrees

step-by-step explanation:

because the lines through the side and the box in the corners shows that these are congruent triangles and since they are mirrored the 37 degrees is also mirrored so the answer is 37 * 2 which is 74.

the answer is true.

step-by-step explanation: