Prove that the conjugate transpose of a matrix product is the product of the conjugate transposes in the opposite order, i. e., (ab)* = b'a . do this in general using indices, i. e., show that ((ab)*); k = (b*a") is using the definitions of conjugate transpose and matrix multiplication and properties of the conjugate.

answer:

probably the same as it is today since you did not eat the corn dogs yet

step-by-step explanation:

i may be incorrect but i believe that her first error was in step one when she multiplyed her equation by 1/4 when she should have divided it by 1/4

graphs that are inverses of each other are graphs where their slopes are reciprocals of each other for example say you have an original equation of y=2x. the inverse of that graph would be y=-1/2(x). also when you see a graph where the original and the inverse is graphed the angle around intersection is 90 degrees.

i never knew that

step-by-step explanation: