using direct substitution, verify that y(t) is a solution of the given differential equations 17-19. then using the initial conditions, determine the constants c or c1 and c2.
17. y ′′ + 4y = 0, y(0) = 1, y ′ (0) = 0, y(t) = c1 cos 2t + c2 sin 2t
18. y ′′ − 5y ′ + 4y = 0, y(0) = 1, y ′ (0) = 0, y(t) = c1et + c2e4t
19. y ′′ + 4y ′ + 13y = 0, y(0) = 1, y ′ (0) = 0, y(t) = c1e-2t cos 3t + c2e-3tsin 3t

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.

just pick what you think i need more time let me know if this

step-by-step explanation:

hi,

the area of abcd is 245.

3*24=230

4*94=1039

2*12=24

add all of them up, you get 2450